56x+9x^2+100=100

Solution for 56x+9x^2+100=100 equation:

56x+9x^2+100=100

We move all terms to the left:

56x+9x^2+100-(100)=0

We add all the numbers together, and all the variables

9x^2+56x=0

a = 9; b = 56; c = 0;
Δ = b2-4ac
Δ = 562-4·9·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-56}{2*9}=\frac{-112}{18}
=-6+2/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+56}{2*9}=\frac{0}{18}
=0
$